3m=27m^2

Solution for 3m=27m^2 equation:

3m=27m^2

We move all terms to the left:

3m-(27m^2)=0

determiningTheFunctionDomain
-27m^2+3m=0

a = -27; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-27)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-27}=\frac{-6}{-54}
=1/9
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-27}=\frac{0}{-54}
=0
$